Question

8. The area of a right angled triangle is 40 sq cm. If its base is equal to 28 cm, find its height.​

Answer 1

Answer:

2.85CM

Step-by-step explanation:

AREA OF RIGHT ANGLED TRIANGLE =1/2×BASE ×HEIGHT

40=1/2×28×HEIGHT

40=14×HEIGHT

HEIGHT =40/14=2.85CM

Answer 2

Question:

• The area of a right angled triangle is 40 cm². If its base is equal to 28 cm, find its height.

Answer:

• Height of right angled triangle is 2.85 cm.

Step-by-step explanation:

Given :

• Area of triangle = 40 cm²
• Base of triangle (b) = 28 cm
• Type of triangle = Right angled triangle

To Find :

• Height of triangle (h)?

Solution :

Here we are using formula of area of right angled triangle to find out its height. As we know that,

• Area of ∆ = ½ × b × h

Where,

• b denotes base of ∆
• h denotes height of ∆

★ According to the Question :

We have,

• Base of ∆ (b) = 28 cm
• Area of ∆ = 40 cm²
• We have to find height of ∆ (h)

Putting all values in formula,

➻ 40 = ½ × 28 × h

➻ 40 = 14 × h

➻ 40/14 = h

➻ 2.85 = h

➻ h = 2.85 cm

• Hence, height of right angled triangle is 2.85 cm.

Extra Information :

• Perimeter of square = 4 × side
• Area of square = (side)²
• Perimeter of equilateral ∆ = 3 × side
• Area of equilateral ∆ = √3/4 (side)²
• Perimeter of rhombus = 4 × side
• Area of rhombus = ½ × d₁ × d₂
• Perimeter of circle = 2πr
• Area of circle = πr²
• Perimeter of rectangle = 2(l + b)
• Area of rectangle = l × b

⊱ ────────── ✯ ────────── ⊰