Question

8. The area of an equilateral triangle of side 4 cm is

Answer 1

We will find the area of triangle by this following steps :

• First , find the s = a + b + c / 2 = 4 + 4 + 4 / 2 = 12 / 2 = 6

         s = 6cm ....

• Then find the area by this formula :

      $\sqrt{ s(s-a)(s-b)(s-c)} sq.unit$

= $\sqrt{6(6-4)(6-4)(6-4)} cm^2$

= $\sqrt{6(2)(2)(2)} cm^2$

= $\sqrt{2*3*2*2*2}$ $cm^{2}$

= $3\sqrt{2*2}$  =  $3\sqrt{4}$ $cm^{2}$ Ans.

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Answer 2

Given :

Side (a) = 4cm

To Find :

Area of triangle

Formula Applied :

$\text{Area of equilateral Triangle } = \sqrt{3} \frac{a^2}{4}$

Solution :

In equilateral triangle  all sides are equal.

$\text{Area of triangle} = \sqrt{3} \frac{a^2}{4}$

$\implies \sqrt{3} \times \frac{4^{2} }{4}$

$\implies \sqrt{3} \times \frac{4 \times 4}{4}$

$\implies \sqrt{3} \times \frac{4}{1}$

$\implies \texttt{4 \sqrt{3} \:cm^2 } \:\:\: (or)\:\:\:\:6.92 cm ^2$