8. The areas of two similar triangles are 49 cm and 25 cm. If the altitude of the first triangle is 2.8 cm ,find the corresponding altitude of the other triangle.
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WKT,
Ratio of area of two similar triangles =ratio of square of corresponding altitudes
Let the altitude of other triangle be x cm
so, 49/25=(2.8)^2/x^2
by solving this equation we will get ,x= 2 cm
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