Question

8. The binding energies of nuclei X and Y are Ej and E2
respectively. Two atoms of X fuse to give one atom of
Y and an energy Q is released. Then
(a) Q = 2E1-E2
(b) Q =E2 - 2E1
(c) Q<2E1-E2
(d) Q > E2-2E1

Answer 1

Answer:

answer : option (c) E1 < E2

explanation : parent nuclei : nucleus present before decay is known as parent nuclei.

daughter nuclei : resultant nucleus or nuclei from decay process is known as daughter nuclei.

in alpha decay process ....

here you can see that number of nucleons in case of daughter nuclei is less than parent nuclei.

if we assume number of nucleons in parent nuclei is A

then, number of nucleons in daughter nuclei is (A - 4)

here obviously , E/(A - 4) > E'/A , where E is binding energy of daughter nuclei and E' is binding energy of parent. but here you should noticed that decay process happens to get stability of nuclei. so, daughter nuclei is more stable than parent nuclei that's why, E/(A - 4) > E'/A

so, E2 > E1

hence, option (c) is correct.