Question

8. The diagonal of a quadrilateral is 30 cm in length and the lengths of
to it from the opposite vertices are 8 cm and 10 cm. Find the
area of the quadrilateral.​

Answer 1

Step-by-step explanation:

If you have a right angled triangle this can be calculated using Pythagoras’ theorem.

If corner B is the right angle then no matter where you put A or C. AC at 17cm must be the hypotenuse (longest side).

Pythagoras theorem usually uses ABC as the names of the sides but to save confusion with the points I will use XYZ. So the theorem is X^2 + Y^2 = Z^2.

X^2 + 15^2 = 17^2 is X^2 + 225 = 289

289 - 225 = 64

Square root of 64 = 8.

So the full formula is 8^2 + 15^2 = 17^2. And the length of AB is 8cm.