8. The diagonals of a rhombus measure 16 cm and 30 cm. Find its perimeter.
Answers
Answered by
9
Answer:
68 cm
Step-by-step explanation:
Let the rhombus be ABCD.
Let the diagonals bisect each other perpendicularly (properties of rhombus) at O.
AO = AC/2
BO = BD/2
∴ ΔAOB will be a right angled triangle
AO² + BO² = AB².
8² + 15² = AB²
64 + 225 = AB²
289 = AB²
AB = √289
AB = 17 cm
∴Perimeter of ABCD = 4 x AB
Perimeter = 68 cm
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Answered by
9
Answer:
diagonals (d1) is 16
diagonal d2 is 30
then perimeter of rhombus =32+60cm
=92
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