Question

8. The diagonals of a rhombus measure 16 cm and 30 cm. Find its perimeter​

Answer 1

Answer:

the half of 1st diagonal is 8

the half of 2nd diagonal is 15

therefore diagonal of rhombus is perpendicular

therefore its form right angle triangle

therefore square of 8 + square of 15 =

64 + 225 = 289

side of rhombus ( hypotenuse) = 289

side of rhombus ( hypo)= 17 cm

perimeter of rhombus = 4 ×side

= 4× 17

=68 cm

Answer 2

Answer:

diagonals of the rhombus  are 16cm and 30 cm

half of the diagonals are 8 cm and 15 cm

so, side of the rhombus is $\sqrt{8^{2} + 13^{2} }$ cm

=$\sqrt{64 + 169}$ cm= $\sqrt{233 }$ cm

so perimeter is 4$\sqrt{233}$ cm

Step-by-step explanation: