Math, asked by vivek9224, 11 months ago

8. The digit at the tens place of a two-digit number is 3 times the digit at the units place. If the digits
are reversed, the new number will be 36 less than the original number. Find the number,​

Answers

Answered by aishu3a
1

Step-by-step explanation:

according to question let,

the unit digit = x

then the tens digit = 3x

because according to question tens digit is 3 times of unit digit.

now the number = 10(3x) + x = 31x

put it eq'n 1 now ,

reversing the original number 10(3x) + x

= 10x + 3x . 10x + 3x

= 31x -36 . 36

= 31x -13x .

next 36 = 18x .

now x = 2 .

put the value of x in eq'n 1 ,

31(2)= 62

the original number obtained is 62

Answered by jinadevkv
1

Answer:

The number is 62

Step-by-step explanation:

Let the digits be x and y.

then the number = 10x + y

x = 3y

If the digits are reversed, the number will be 10y + x

10y + x = 10x + y - 36

9x - 9y = 36

27y - 9y = 36

18y = 36

y = 36/18 = 2

x = 3y = 6

The number = 62

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