Question

8. The equation of the line PQ is 3y - 3x + 7 = 0.
(1) Write down the slope of the line PQ.
(i) Calculate the angle that the line PQ makes with the positive dire3zction qof x-axisrt ź .​

Answer 1

Answer:

Given, equation of line PQ is 3y−3x+7=0

Re-writing in form of y= mx+c, we have

3y=3x−7

$y = x + \frac{ - 1}{3}$

Here,

(i) slope= 1

(ii) As tanθ =0

θ= 45°

Hence, the angle which PQ makes with the x-axis is Q

Thanks