Question

8. The equivalent resistance of
parallel combination of three
resistances of 3 ohm ?
O 9 ohm
O 6 ohm
O 01 ohm
>
O 12 ohm​

Answer 1

Answer:

So you have 3 equal resistors in parallel. To find the total we have to use this formula:

1/R1+1/R2+1/R3+…+1/Rn=1/R(total)

You have 3 equal ones and know the total (equivalent) resistance. That means: 1/R+1/R+1/R=1/(1Ω)

You can now solve for R:

3/R=1/(1Ω)

R/3=1Ω

R=3Ω

For resistors in series you just have to add them up to get equivalent resistance: R(total)=R1+R2+R3+…+Rn

Now just sum up: 3Ω+3Ω+3Ω=9Ω So the equivalent resistance when they are connected in series is 9Ω.

Explanation: