Question

| 8.
The focus of the parabola y^2 – 4y -x+3=0 is
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Answer 1

the parabola given is

${y}^{2} - 4y + 4 = x + 1 \\ {(y - 2)}^{2} = x + 1$

let Y = y-2

and, X=x+1

therefore,

(Y)^2 = (4/4)X

here, a = 1/4

co-ordinates of focus can be found out by putting

X=a = 1/4

Y=0

so, coordinates comes out to be

$( \frac{ - 3}{4} \: . \: 2)$