Economy, asked by aditisingla082002, 7 months ago

8. The following series relates to the daily income of working employed in a firm. Compute
(1) highest income of lowest 50% workers (ii) minimum income earned by the top 25% of the
workers, and (iv) maximum income earned by lowest 25% workers:
Daily Income (Rs.):
10-14
15-19
20-24
25-29
30-34
35-39
No. of Workers:
5
10
15
20
10
5
[Hint: Compute Median, Upper Quartile and Lower Quartile]
[Ans. (i) Rs. 25.11 (ii) Rs. 29.19 (iii) Rs. 19.92]​

Answers

Answered by ovipranav
1

Answer:

Interval               No. of Workers

(f  

i

​  

)                            Class Mark (x  

i

​  

)           Deviation

d  

i

​  

=  

h

x  

i

​  

−A

​  

              f  

i

​  

d  

i

​  

 

20−24 2 22 −2 −4

25−29 10 27 −1 −10

$30 - 34$$ 15 32→A 0 0

35−39 20 37 1 20

40−49 28 42 2 56

45−49 25 47 3 75

Total  

∑f  

i

​  

=100    

∑f  

i

​  

d  

i

​  

=137

Assumed Mean (A)=32 and h=5

∴ Mean(  

x

)=A+  

∑f  

i

​  

 

h∑f  

i

​  

d  

i

​  

 

​  

 

x

=32+  

100

5×137

​  

 

=32+6.85

=38.85

Explanation:

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