Question

8.
The inner diameter of a cylindrical wooden pipe is 24cm and its outer
diameter is 28cm - The length of this pipe is 35cm. Find the mass of
the pipe if 1 cm' of wood has a mass of 0.6 gram.​

Answer 1

Answer:

Here, inner radius (r) = 24/ 2 cm = 12 cm Outer radius (R) = 28/ 2 cm = 14 cm, h = 35 cm Volume of the wood used in the pipe = π(R2 – r2) h = 22/ 7 [(14)4 – (12)2] × 35 cm3 = 22/ 7 × 26 × 2 × 35 cm3 = 5720 cm3 Mass of 1 cm3 of wood = 0.6 g ∴ Mass of 5720 cm3 of wood = 0.6 × 5720 g = 3432 g = 3.432 kg Ans.Read more on Sarthaks.com - https://www.sarthaks.com/12178/the-inner-diameter-cylindrical-wooden-pipe-cm-and-its-outer-diameter-is-the-length-the-pipe

Step-by-step explanation:

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Answer 2

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