English, asked by nishan2788, 6 months ago

8. The L.C.M. of three different numbers is 240.
Which of the following cannot be their H.C.F.?
(a) 8
(b) 12 (c) 24
(d) 35 (e) None of these​

Answers

Answered by mahimaa19
0

Answer:

35 is the correct answer

Answered by AnkitaSahni
2

(d)35 can not be their HCF.

Given:

The L.C.M. of three different numbers is 240.

To Find:

We have to find which of the following cannot be their H.C.F.

Solution:

This is a problem for LCM and HCF.

Let us tackle the problem.

We can easily solve this problem as follows.

We can see that,

240 = 2×2×2×2×3×5 ...............(i)

So, the HCF of those three numbers can be

2×2×2 = 8

or, 2×2×3= 12

or 2×2×2×3 = 24

As we can see 34=5×7, but there is no 7 in (i).

Hence, 35 can not be their HCF.

#SPJ2

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