Question

8. The last term of the G.P:3, 3,3√3,9, ... is 2187.
How many terms in all are there in the G.P?​

Answer 1

Hie!!

Given G.P is 3 , 3√3 , 9 ... , 2187

Last term of G.P is given by

L = arⁿ-¹

Here L = 2187 , a = 3 , r = 3√3/3 = √3

2187 = 3 × ( √3 )ⁿ-¹

729 = (√3)ⁿ-¹

3^6 = (√3)ⁿ-¹ {. Becoz 3^6 = 729 }

3^6 = {3}^ (n-1)/2

Now, Compare powers of 3 we have

6 = (n - 1 )/2

12 = ( n -1 )

n = 12 + 1

n = 13

So, the number of terms in this series is 13.

Answer 2

Answer:

Step-by-step explanation: