Question

8) The LCM of two numbers is 630 and their HCF
is 9. If one number is 90, then find the other
number
(a) 53
(b) 63
(c) 93
(d) 73​

Answer 1

Answer:

63

Step-by-step explanation:

630×9 = 90×X

630×9÷90 = X

63 = X.

Answer 2

Step-by-step explanation:

HCF × LCM = Product of numbers

Given : HCF= 9

LCM= 630

One number= 90

another be= x

630 × 9 = 90 × x

$\frac{630~×~9}{90}~=~x$

(take 90 to LHS ,it will be division)

63 = x

63 is your answer