Question

8. The length and breadth of a rectangle are 18 m and 12 m respectively. If its

perimeter is equal to perimeter of a square, find the side of the square.​

Answer 1

Answer:

✮Formula used:

Perimeter of the rectangle=2(Length+Breadth)

✮Solution:

Given:

Length=18m

Breadth=12m

Perimeter of the rectangle= 2(18+12)

⇒2× 30m

⇒60m

Perimeter of the square= 4× side

$⇒Side= \frac{perimeter}{4}$

$⇒Side= \frac{60}{4}$

$⇒Side=15m$

Therefore, The side of the square is 15m.

Answer 2

Analysis→

Here the question conveys that the breadth of a rectangle is 12m and length is 18m. And the perimeter of the rectangle and is equal to the perimeter of a square. And we've to find the side of the square. And we know that:

$\rm{Perimeter\:of\:rectangle=2(l+b)}$

$\rm{Perimeter\:of\:square=4(s)}$

Given→

• Length of rectangle=18cm
• Breadth of rectangle=12cm
• Side of square= (let be s)
• Perimeter of rectangle=Perimeter of square

To Find→

The side of the square.

Answer→

$\large{\underline{\boxed{\leadsto{\rm{Perimeter_{Rectangle}=Perimeter_{Square}}}}}}$

$\large{\underline{\boxed{\leadsto{\rm{2(l+b)=4(s)}}}}}$

$\implies\rm{2(l+b)=4(s)}$

$\implies\rm{2(18cm+12cm)=4(s)}$

$\implies\rm{2(30cm)=4(s)}$

$\implies\rm{60cm=4(s)}$

$\implies\rm{s=\dfrac{60cm}{4}}$

$\implies\rm{s=\dfrac{\cancel{60cm}}{\cancel{4}}}$

$\implies\rm{s=15cm}$

${\boxed{\boxed{\implies{\bf{s=15cm\checkmark}}}}}$

☞ Hence the side of the square is 15cm which is the required answer.

HOPE IT HELPS.