Question

8. The length, breadth and height of a room are 8 m 50 cm, 5 m 75 cm and 1 m 75 cm respectively. Find
the length of the longest tape which can measure the three dimensions of the room.
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Answer 1

$➪ \sf \red{Answer:-}$

$\huge{ ➫} \tt GIVEN:-$

$length \: of \: room \: = 7m25cm = 725cm \\ breadth \: of \: room \: = 9m25cm = 925cm \\ height \: of \: room \: = 8m25cm = 825cm$

$\huge ➫ \sf FIND:-$

$now \: we \: find \: HCF \: of \: 725,925 \: and \: 825$

${\huge ➫ {\mathfrak{Solution:-}}}$

$725 = 5 \times 5 \times29 \\ 925 = 5 \times 5 \times 37 \\ 825 = 3 \times 5 \times 5 \times 11 \\ \\ so, \: heighest \: common \: factor \: is \: 5 \times 5 = 25 \\ therefore \: HCF \: of \: 725,925,825 \: is \: 25. \\ \therefore 25m is \: the \: longest \: tape \: measure \: which \: can \: measure \: all \: the \: dimensions.$

$so, \: answer \: is \: \boxed{ \mathfrak{ 25m}}$