8. The length of a chain used as the boundary of a semicircular park is
90 m. Find the area of the park.
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Length of the boundary of the semicircular park = 90 m
→πr + 2r =90
→r(22/7 + 2) = 90
→r = (90×7)/36
→r = 17.5 m
Area of the semicircular park = 1/2πr²
= 1/2×22/7×17.5×17.5
= 481.25 sq m
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