Question

8) The length of a rectangle is 10 m more than its breadth. If the perimeter of rectangle is 80 m. find the
dimensions of the rectangle.

pls answer quickly.​

Answer 1

$\large{\mathfrak{\underline{\underline{Answer:-}}}}$

Length = 25 m

Breadth = 15 m

${\mathfrak{\underline{\underline{Step-By-Step-Explanation:-}}}}$

Let breadth of rectangle be x .

Then,

Breadth = x .........(1)

length = x + 10 .........(2)

____________________________

A.T.Q,

$\large{\sf{\star{\boxed{\boxed{Perimeter \: = \: 2(length \: + \: breadth)}}}}}$

__________________[Put values]

⇒ 80 = 2(x + x + 10)

⇒80 = 2(2x + 10)

⇒80/2 = 2x + 10

⇒ 40 - 10 = 2x

⇒ 30 = 2x

⇒x = 30/2

⇒ x = 15

Breadth (X) = 15 m

Substitute value in (1)

⇒ length = x + 10

⇒length = 15 + 10

⇒ length = 25

Lengtht = 25 m

__________________________

$\large{\mathfrak{\underline{\underline{Proof:-}}}}$

Perimeter = 2(length + breadth)

80 = 2(15 + 25)

80 = 2(40)

80 = 80

Hence Proved

Answer 2

Answer :-

25 m and 15 m are the dimensions of the rectangle.

Solution :-

Let the breadth of a rectangle be 'x' m

Length of the rectangle = 10 m more than its breadth = (x + 10) m

Given

Perimeter of the rectangle = 80 m

⇒ 2(Length + Breadth) = 80 m

⇒ 2(x + 10 + x) = 80

⇒ 2(2x + 10) = 80

⇒ 2x + 10 = 80/2

⇒ 2x + 10 = 40

⇒ 2x = 40 - 10

⇒ 2x = 30

⇒ x = 30/2

⇒ x = 15

Breadth of the rectangle = x = 15 m

Length of the rectangle = (x + 10) = (15 + 10) = 25 m

Therefore 25 m and 15 m are the dimensions of the rectangle.