Question

8. The length of each side of a rhombus is 10 cm and one of its diagonals
is of length 16 cm. The length of the other diagonal is
(a) 13 cm
b) 12 cm
(c) 2√39cm
d ) 6cm​

Answer 1

Diagonal of a rhombus bisect each other at right angles .

Let ABCD be the rhombus , Diagonal AC =16 cm and side AB =10 cm

-: In right triangles AOB , AB=10cm AO 8 cm

By PYTHAGORAS THEOREM,

$( {ab)}^{2} = {ao}^{2} + {bo}^{2}$

$= > {10}^{2} = {(8)}^{2} + ({bo})^{2}$

$= > {bo}^{2} = {10}^{2} - {8}^{2}$

$= > bo = 6$

Diagonal BD = 2×6= 12

Answer 2

Answer:

B .12 cm,,,,,,,,,,,,, please mark at brainlist friend