8. The length of each side of a rhombus is 10 cm and one of its diagonals
is of length 16 cm. The length of the other diagonal is
(a) 13 cm (b) 12 cm (c) 239 cm (d) 6 cm
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Answer:
b
Explanation:
Diagonals of a rhombus bisect each other at right angles.
Let ABCD be the rhombus, Diagonal AC=16 cm and side AB=10 cm.
In right △AOB, AB=10 cm, AO=8 cm
By Pythagoras theorem, AB^2 =AO^2 +BO^2
⇒10^2 =8^2 +BO^2
⇒BO ^2=100−64=36
∴BO=6cms
Diagonal BD=2×6=12cm
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