Question

8. The linear momentum of a particle of particles of mass 1kg and kinetic energy 2J is equal to
​

Answer 1

Answer:

Correct option is

D

(d) 450 J

Initial velocity (u)=  

5

20

​

=4m/s

Acceleration produced =  

m

F

​

=1m/s  

2

 

Final velocity(v)=u+at=4+1(10)=14

So, Change in K.E =  

2

1

​

m(v  

2

−u  

2

)=  

2

1

​

(5)(196−16)=450J

Therefore, D is correct option.

Step-by-step explanation: