Math, asked by ishneetkaur6641, 1 day ago

8. The maximum temperatures (in degree celcius) for a city in North India for the month of June 2000, as reported by meteorological department are as below 32.4, 30.3, 31.6, 32.5, 33.5, 28.7, 33.4, 35.6, 36.4, 34.7, 35.2, 30.6, 28.5, 29.4, 30.3, 32.5, 34.6, 35.4, 36.1, 37.2, 28.5, 28.1, 29.2, 31.4, 32.5, 36.2, 35.9, 36.7, 37.2, 36.1, then range is​

Answers

Answered by subhalaxmi70
16

Answer:

Range = 37.2- 28.1 = 9.1

Hope it helps

Answered by amitnrw
3

Given  : The maximum temperatures (in degree celcius) for a city in North India for the month of June 2000, as reported by meteorological department  

To Find : range

Solution:

Range is Highest value - Lowest Value

Data is :

32.4, 30.3, 31.6, 32.5, 33.5, 28.7, 33.4, 35.6, 36.4, 34.7, 35.2, 30.6, 28.5, 29.4, 30.3, 32.5, 34.6, 35.4, 36.1, 37.2, 28.5, 28.1, 29.2, 31.4, 32.5, 36.2, 35.9, 36.7, 37.2, 36.1,

Lowest is 28.1

Highest is  37.2

Range = 37.2 - 28.1   = 9.1

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