8) The measure of one side of right triangular field is 42cm. if the difference of the lengths of hypotenuse and the other is 14cm. Find the side of the triangle and its area
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Answer:
Area of triangular field = 1176m²
Step-by-step explanation:
AB = 42m
Let BC be a and AC be h
hence h = x + 14
by Pythagoras theorem we can say that
h² = x² + (42)²
(x + 14)² = x² + (42)²
x² + 28x + 196 + x2 - 1764 = 0
28x - 1568 = 0
28x = 1568
x = 56
hence h = 70m
Area of triangular field =
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