Question

8) The measure of one side of right triangular field is 42cm. if the difference of the lengths of hypotenuse and the other is 14cm. Find the side of the triangle and its area

Answer 1

Answer:

Area of triangular field = 1176m²

Step-by-step explanation:

AB = 42m

Let BC be a and AC be h

hence h = x + 14

by Pythagoras theorem we can say that

h² = x² + (42)²

(x + 14)² = x² + (42)²

x² + 28x + 196 + x2 - 1764 = 0

28x - 1568 = 0

28x = 1568

x = 56

hence h = 70m

Area of triangular field =

$= \frac{1}{2} \times 42 \times 56 \\ = 1176 {m}^{2}$