Question

8. The number of values of a lying in [-pi, pi] and
satisfying 2sin(2a) = cos(2a) and sin(2a) + 2cos(2a) –
cos(a) - 1 = 0 is​

Answer 1

Answer:

. The number of values of a lying in [-pi, pi] and satisfying 2sin(2a) = cos(2a) and sin(2a) + 2cos(2a) – cos(a) - 1 = 0 is