Question

8. The numerator of a fraction is smaller than its denominator by 1. If the numerator is
increased by 4 and the denominator is doubled the number becomes 1. Find the fraction.​

Answer 1

Answer:

Required Answer :-

Let the fraction be x - 1/x

$\sf \dfrac{x - 1 + 4}{2x} = 1$

$\sf \: \dfrac{x + 3}{2x} = 1$

$\sf \: x + 3 = 2x$

$\sf \: 2x - x = 3$

$\sf \: x = 3$

Fraction = 3 - 1 + 4/2(3)

Fraction = 2/3

V E R I F I C A T I O N :

$\sf \: \dfrac{3 - 1 + 4}{2(3)} = 1$

$\sf \: \dfrac{7 - 1}{6} = 1$

$\sf \: \dfrac{6 }{6} = 1$

$\sf \: 1 = 1$

Answer 2

Question:-

• The numerator of a fraction is smaller than its denominator by 1. If the numerator is increased by 4 and the denominator is doubled the number becomes 1. Find the fraction.

To Find:-

• Find the fraction.

Solution:-

Here ,

• Let numerator be x - 1

• Denominator be x

According to the Question:-

$\tt\implies \: \dfrac { x - 1 + 4 } { 2x } = 1$

$\tt\implies \: x + 3 = 2x$

$\tt\implies \: 2x - x = 3$

$\tt\implies \: x = 3$

Hence ,

• Denominator is 3

• Numerator is x - 1 = 2