Question

8) The perimeter of a rectangle is 60 metres. If its length is twice its breadth, then its area is:

Answer 1

Hello !
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Perimeter of rectangle : = 60 m 
let breadth = b
ATQ
length = 2b
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Perimeter = 2(length + breadth )
                 = 2( 2b + b) 
                 = 4b + 2b 
                 = 6b 
ATGC 
6b = 60 m
b   = 10 m
l    = 2 x 10 = 20 m
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Area of rectangle = length x breadth 
                             = 20 X 10 = 200 m²
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Answer 2

hello there!!!!
let the length of the rectangle be ' x 'm
and breadth be y m
perimeter of o rectangle = 60 m
As we know that P = 2 (l+ b)
60 = 2 ( x+ y)
x+ y = 30........... ...........(1)
ATQ,
x= 2y , then put the value of x in eq 1 , we get,
y+ 2y = 30
3y = 30
y= 10m...................(2)
Now , x + 10 = 30
x= 20 m
Area of the rectangle = l× b
= 20 × 10 = 200m²
hope it helps you