Question

8) The perimeter of a square is (4x+20)cm. What will be the length of its diagonal?
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Answer 1

Given :

• The perimeter of a square is (4x+20)cm.

To Find :

• Length of digonal = ?

Solution :

◓ Perimeter of square = 4 × a

➨ 4x + 20 = 4a

➨ a = $\sf \dfrac{4x + 20}{4}$

➨ a = $\sf \dfrac{4(x + 5)}{4}$

➨ a = x + 5

Now, we need to find diagonal of square :

★ Diagonal of square = √2 × side

★ Diagonal of square = √2 (x + 5) cm

Therefore, the diagonal of the square is √2(x + 5) cm.

Answer 2

▪ Question -

Perimeter of square is (4x+20)cm.

▪ To Find -

Length of the Diagonal.

▪ Solution -

☆ We Know that, Perimeter of square = 4 × a

So, It will become,

$⟹a = \frac{4x + 20}{4}$

$⟹a = \frac{4(x + 5)}{4}$

$⟹\frac{\cancel{4(x+5)}}{\cancel{4}}$

$⟹a = x + 5$

☆ Diagonal Of Square = √2×side

So, It will become,

$⟹ \sqrt{2} \times (x + 5)$

$⟹ \sqrt{2} (x + 5)$

⛬ The Length Of diagonal is √2(x+5)cm