Question

8. The persent age of Sreelata is 2/7th of Pinki's present age and seven years ago Pinki's age was 5 times the present age of Ronit. If after 18 vears Ronit will be 25 years old, then what is the present age (in years) of Sreelata ? 1) 15 3) 22 4) 18 5) 12 2) 10​

Answer 1

Answer:

12

Step-by-step explanation:

S = 2/7 × P

P - 7 = 5R

R + 18 = 25

R = 25 -18

R= 7

P-7 = 5×7

P-7 = 35

P = 35+7

P= 42

S = 2/7 × 42 = 2×6

S = 12

Answer 2

$\large\underline{\sf{Solution-}}$

Given that,

• The persent age of Sreelata is 2/7th of Pinki's present age.

• Seven years ago, Pinki's age was 5 times the present age of Ronit.

• After 18 years, Ronit will be 25 years old.

Step :- 1

Let assume that present age of Ronit be x years.

So, after 18 years, Ronit age will be x + 18 years.

According to statement, after 18 years, Ronit will be 25 years old.

$\rm \: x + 18 = 25$

$\rm\implies \:\boxed{ \rm{ \:x = 7 \: \: }}$

So, Ronit present age is 7 years.

Step :- 2

Let assume that present age of Pinki be y years.

So, 7 years ago, her age was (y - 7) years

Now, given that seven years ago, Pinki age was 5 times the present age of Ronit.

$\rm \: y - 7 = 5 \times 7$

$\rm \: y - 7 = 35$

$\rm\implies \:\boxed{ \rm{ \:y = 42 \: }}$

So, present age of Pinki is 42 years.

Step :- 3

Now, given that

$\sf \: Sreelata \: present \: age = \dfrac{2}{7} \: of \: present \: age \: of \: Pinki$

$\sf \: Sreelata \: present \: age = \dfrac{2}{7} \: \times 42$

$\sf \: Sreelata \: present \: age = 2 \times 6$

$\red{\rm\implies \:\boxed{ \rm{ \:\sf \: Sreelata \: present \: age = 12 \: years \: \: }}}$