Math, asked by sanskritipramanick, 4 months ago

8. The population of a city increases 10%
every 3 years. if the present population of the
city is 72,600 , what was its population 6
years ago ?​


Anonymous: Tq

Answers

Answered by Anonymous
3

Step-by-step explanation:

Let population 6 years ago=100

Then population 3 years ago =100+10 %of 100

=100+10

=110

And present population=110+10% of 110

=110+11

=121

When presente population is 121 ,population 6 years ago=100

When present population 72,600,population 6 years ago

=100×72,600/121

=60,000

Answered by amulyaphule25
1

Answer:

Let population 6 years ago = 100

 Then population 3 years ago = 100 + 10% of 100

                                           = 100 + 10

                                           = 110

And present population = 110 + 10% of 110

                                  = 110 + 11

                                  = 121

When present population is 121, population 6 years ago= 100

When present population is 72,600, population 6 years ago

 =100×72,600/121

=60.000

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