Question

8. The population of town is 8000. It increases by 10% during first year and by 20% during second year. Find the population after 2 years.​

Answer 1

Answer:

9696

Step-by-step explanation:

At first we would do the following

10/100*8000=800/10=80/1

Therefore the population in the first year was 8000+80=8080

Now,

20/100*8080=16160/10=1616/1

Therefore the population in the second year is 8080+1616=9696

The population is 9696 in the second year

Answer 2

$\huge\sf\color{red}{Answer }$

$\underbrace \mathfrak{population \: of \: town \: after \: 2 \: years :}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \implies \: \: \: 8000 \times (1 + \frac{10}{100} ) \times (1 + \frac{20}{100} ) \\ \\ \sf \implies 8000 \times \frac{11}{10} \times \frac{6}{5} = 10560$

105,60 is the answer