Question

8.
The product of two numbers is 4107. If the
H.C.F. of these numbers is 37, then find the
greater number.
​

Answer 1

Answer:

111

Step-by-step explanation: Let the numbers be 37a and 37b. Then , 37a x 37b =4107  => ab = 3.

Now co-primes with product 3 are (1,3)

So, the required numbers are (37 x 1, 37 x 3) i.e, (37,111).

Therefore, Greater number = 111.