Question

8. The refractive index of the medium 'x' with respect to the medium 'y is 2/3 and the
refractive index of medium 'y with respect to medium 'z' is 4/3. Find the refractive index
of medium 'z' with respect to medium 'X'. If the speed of light in medium 'x' is 3x10 ms
calculate the speed of light in medium 'y'.​

Answer 1

Answer:

you have to x×y so then you can find your medium the light which they was staring it's an interesting qoustion right ok thanks by bye

Answer 2

Answer:

2×10⁸

Explanation:

We know that the refractive index of medium 1 with respect to medium 2 is reciprocal to the refractive index of medium 2 with respect to medium 1.

Therefore,

The refractive index of medium ‘z’ with respect to medium ‘x’, nzx is given as-

nzx = nz/nx = nzy × nyz = nz/ny × ny/nx

Therefore,

nzx = 1/nyz × 1/nxy (∵nzy=1/nyz)

nzx=1/ny/nz × 1/nx/ny

nzx = 1/4/3 × 1/2/3

nzx = 3/4 × 3/2

nzx = 9/8

Thus, the refractive index of medium ‘z’ with respect to medium ‘x’, nzx is 98.

Let the speed of light in medium ‘y’ be ‘V’, and the speed of light in medium ‘x’ be ‘C’ i.e. 3×108ms−1.

Therefore,

nyx, or ny/nx ⇒ 1/nxy ⇒1/nx/ny ⇒ 1/2/3 ⇒ 3/2

nyx, or ny/nx =3/2 (∵nyx=1/nxy)

y/x=3/2 ………………. (1)

C/V = 3×108/V ………………. (2)

Equating (1) and (2) we get-

3/2 = 3× 108/V

3 × V = 2×3×108

3×V = 6×108

V = 6×108/3

V=2×108

Thus, the speed of light in the medium ‘y’ is 2×108.