Question

8. The resistance of a conductivity cell containing 0.001M KCl solution at 298K is 1500. What is
the cell constant (in mm). If the conductivity of 0.001 M KCl solution is 2x10 sm
a) 1
b) 2
04
C) 3​

Answer 1

Answer:

(C) 3

Explanation:

conductivity, k = G × G*

2 × 10 = G*/1500