Question

8) The resonant frequency of a circuit point is f. If the capacitance is made 4 times the initial value , then the resonant frequency will become ​

Answer 1

Answer:

Explanation:

given

the resonant frequency is f0

(a)L1=4L

where ,L is initial inductance of the LC circuit.

f0(new)=1/2 pie root L1 c

            =1/2 pie root 4LC

            =1/4 pie root L C

Hence, if the inductor is increased by the factor of 4. Then, new resonant frequency will decrease by factor of 2.

(b) if f0(new)=f0

then,

f0=1/2$\pi$ root LC

   =1/2 $\pi$ root 4*L*C/4

Hence, if the new resonant frequency changes to initial resonance frequency. Then, capacitor will decrease by factor of 4.

hope u have been understood

no copied

mark me as brainlist