8. The shape of a garden is, as shown in the adjoining
figure, semicircular at the ends and rectangular in the
middle. Find the area and perimeter of the garden.
[HINT: Length of rectangle = 250 - 2r.)
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Answered by
31
Answer:
Area =30800sqm and Perimeter = 940m
Step-by-step explanation:
Length of the rectangle = 250-2r (Given)
width is given as 140, which is the diameter of the semi circle
Radius =Diameter/2=140/2=70
Length of the rectangle = 250-2(70)=250-140=110
Area of the rectangle = Length * Breadth = 110*140=15400sq.m
Area of the semi circle = 1/2 πr²
Then area of both semi circles = 2 * 1/2 πr² = πr² =22/7 *70²=15400sq.m
Total Area= 15400 + 15400 =30800sqm.
Perimeter of rectangle = 2 (Length + Breadth)
= 2(110+140)=2*250=500m
Circumference (Perimeter) of semicircle= 1/2 * (2πr)
Circumference (Perimeter) of both semicircles = 2*1/2*(2πr)
=2*22/7*70 =440m
Total Perimeter of the garden = 440+500=940m
Answered by
6
Answer:
perimeter is 660m and area is correct
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