Question

8. The speed of a motor launch with respect to water in
a stream is 8 ms', while water current's speed is 3
ms'. When the launch began travelling upstream, a
float was dropped from it. After travelling a distance
of 4.8 km upstream, the launch turned back and caught
up with the float. What is the total time which elapsed
during the
process?​

Answer 1

Answer:

Explanation:

tAB=tAC+tCB

xu4.8v−u+4.8+xv−u ltbtgt x3=4.88−3+4.8+x8+3⇒x=28.8/5km

Time take: xu=28.8×10005×3=1920s=32min.