Question

8. The speed-time graph for a car is shown is Fig. 8.12.
Speed (ms)
2
8
10
6
Time (s)
Fig. 8.12
(a) Find how far does the car travel in the first 4 seconds.
Shade the area on the graph that represents the distance
travelled by the car during the period.
(b) Which part of the graph represents uniform motion of the
car?​

Answer 1

Answer:

The total number of divisions on horizontal axis for 2 s is 5.

The total number of divisions on vertical axis for 2 m/s is 3.

The total displacement of the car during these two seconds will be given as the area under all these squares.

The area under the (3×5) squares is given as:

A

15

=2×2 = 4

So, the area under one small square is :

A

1

=

15

4

Now, the area under the graph for 4 sec is:

the number of squares under the graph is :

n=57 small squares + 6 half small squares

So, total number of squares =60.

So, the distance traveled by the car is the area under the curve.

S=60×

15

4

S=16 m