Math, asked by ridhman15, 1 year ago

8. The sum of a two digit number and the number obtained by reversing the digits is 55. If the digits of a number differ by 1, find the number.

Answers

Answered by shivani3155
1

Answer:

obtained number is 32

Step-by-step explanation:

let the two digit number = 10x + y

A.T.Q

(10x + y) + (10y + x) = 55

10x + y + 10y + x = 55

11x + 11y = 55

divide by 11

x + y = 5 -------------(1)

x - y = 1 -----------(2)

on adding eq 1 and 2

x + y = 5

x - y = 1

2x = 6

x = 6/2

x = 3

pyt x in eq 1

x + y = 5

3 + y = 5

y = 5 - 3

y = 2

number is 10x + y

= 10 × 3 + 2

= 30 + 2

= 32

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