8. The sum of a two digit number and the number obtained by reversing the digits is 55. If the digits of a number differ by 1, find the number.
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Answer:
obtained number is 32
Step-by-step explanation:
let the two digit number = 10x + y
A.T.Q
(10x + y) + (10y + x) = 55
10x + y + 10y + x = 55
11x + 11y = 55
divide by 11
x + y = 5 -------------(1)
x - y = 1 -----------(2)
on adding eq 1 and 2
x + y = 5
x - y = 1
2x = 6
x = 6/2
x = 3
pyt x in eq 1
x + y = 5
3 + y = 5
y = 5 - 3
y = 2
number is 10x + y
= 10 × 3 + 2
= 30 + 2
= 32
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