Question

8. The sum of five consecutive even numbers is 660. What is the sum of the greatest and the smallest among them? (1) 132 (2) 264 (3) 364 (4) 426
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Answer 1

Answer:

Step-by-step explanation:

Let  five consecutive even numbers x,(x+2),(x+4),(x+6),(x+8)

x+(x+2)+(x+4)+(x+6)+(x+8)=660

5x+20=660

x=(660–20)/5x=128.

Then sum of the greatest and and smallest nunber is (x+8)+x

= (128+8)+128

= 264.

Answer 2

To find : sum of the greatest and the smallest  

Given : The sum of five consecutive even numbers is 660.

Solution :

• Let , five consecutive even numbers be , $x , ( x+ 2 ), (x + 4), (x + 6 ) , (x+ 8 )$.
• According to given condition we have , $x + ( x+ 2 ) + (x + 4) + (x + 6 ) + (x+ 8 ) =660$
• Adding terms we get , $5x + 20 =660$

                                              $x = \frac{640}{5}$

                                              $x = 128$

• Therefore , smallest number is , $x = 128$ and largest number is , $x + 8 = 128 + 8$

                 $= 136$

sum of the greatest and the smallest  : $128 + 136 = 264$