Question

8. The sum of four integers in A.P. is 24 and their product is 945. Find them.
[Hint. Select the numbers to be a - 3d, a-d, a + d, and a + 3d​

Answer 1

Answer:

the sum of four integers

a-3d +a-d+a+d +a+3d=24

a+a+a+a-3d-d+d+3d =24

4a-4d+4d=24

4a=24

a=24/4

a=6

And the product

a-3d (a-d)+a+d (a+3d)=945

a (a-d)-3d (a-d)+a (a+3d)+d (a+d)=945

a^2-ad-3ad+3d^2 +a^2+3ad+da+d^2=945

a^2+a^2-ad-3ad+3ad+ad+3d^2+d^2=945

2a^2+4d^2=945

2a+4d=945

2a+d=945/4

2a+d =236

a+d=236/2

ad=118