Question

8. The sum of the digits of a 2-digit number is 6. On reversing its digits, the number is 18 less than the
original number. Find the number​

Answer 1

Answer:

Digit sum of a two digit number is 6:

x+y=6

Reverse the digits and you get 18 less than the original value:

10y+x=10x+y-18

Now let's solve:

y=6-x

10(6-x)+x=10x+(6-x)-18

60-10x+x=10x+(6-x)-18

60-9x=9x-12

72=18x

x=4

y=6-4

y=2

So our original number was 42. Sum of digits is 6. Swap the order of the digits to make 24, and you have a number 18 less than the original number.

Answer 2

Answer:

the original no. is 42

Step-by-step explanation:

let this be

x+y=42... eq 1

now acc. to the question

10y+x=10x+y+18... eq 2

solving this we will get

x=4 and y=2