Question

8. The sum of the digits of a 2-digit number is 9. On
reversing its digits, the new number obtained is 45
more than the original number. Find the number.​

Answer 1

Answer:

Ans)27

Step-by-step explanation:

Let the original number be in the form 10x+y and the reverse is 10y+x.

Given (x+y) =9...(i)

On reversing the digits we get (10y+x)=45+10x+y

Then,

9y-9x=45

9(y-x)=45

Y-x=5......(ii)

From equation (i) & (ii) we get,

X+y=9

Y-x=5

On adding both equations,

2y = 14

Y = 7

X= 2

So the original number is 10x+y therefore the number is 27.

Answer 2

$\huge\underline\mathfrak\red{Answer}$

$\huge\boxed{Required\:Number\:=\:27}$

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$\huge\underline\mathfrak\red{Explanation}$

Refer to the attachment!!

In the attachment,

I've take x as unit digit and y as tens digit.

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