(8) The sum of the first five multiples of 3 is ...
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45
Step-by-step explanation:
a = 3 ( first term)
d = 6-3 = 3 ( second term - first term = common difference )
L = 15 ( last term )
Sn = n/2 (a + L )
Sn = 5 /2 ( 3 + 15 )
Sn = 5/2 ( 18 )
Sn = 5 ( 9 )
Sn = 45
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The first 5 multiples of 3 are:-
3×1=3
3×2=6
3×3=9
3×4=12
3×5=15
The sum of first 5 multiples of 3 is =3+6+9+12+15=45
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