Question

(8) The sum
of three consecutive integers is 36. Find the integers.​

Answer 1

Answer:

11,12 and 13

Step-by-step explanation:

Let the middle most Integer be x

then 1st integer is x-1

and the 3rd integer is x+1

now their sum in 35

so

x-1+x+x+1=36

3x=36

x=12

so 1st integer =11

and 3rd integer =13

and 3 integers are 11,12 and 13

Answer 2

Answer:

Let the integers be x, (x+1), (x+2)

According to question

x+(x+1)+(x+2)=36

=>x+x+1+x+2=36

=>3x+3=36

=>3x=36-3

=>3x=33

=>x=33/3

=>x=11

Therefore

The three consecutive integers are 11, 12 and 13