Physics, asked by ash2904, 3 months ago

8
The two simple harmonic motion are represented by
Y = 5Sin cos(wt+π/2) and Y, = -12 Cos(wt). The resultant amplitude of simple harmonic motion will
be:
(1)7
(2) 13
3) 12
(4) √5 +√12​

Answers

Answered by amoghnasa
0

Resultant amplitude of two SHM wave will be,

 \sqrt{a1 {}^{2}  + a2 {}^{2} }

 \sqrt{5 { }^{2}  + 12 { }^{2} }

√25+144=✓169 = 13

ans - 2) 13

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