Question

8. The velocity of an object increases at a consta
rate from 20 m s-1 to 50 m s-1 in 10 s. Find i
acceleration.​

Answer 1

The acceleration of a body is defined as the rate of change of its velocity.

It is the change in velocity per unit time.

$\sf{\longrightarrow Acceleration=\dfrac{Change\ in\ Velocity}{Time}}$

We know change in velocity is the difference in initial and final velocity.

$\sf{\longrightarrow Acceleration=\dfrac{Final\ Velocity-Initial\ Velocity}{Time}}$

$\sf{\longrightarrow a=\dfrac{v_f-v_i}{t}}$

Unit $\sf{=m\,s^{-1}}$

Dimension $\sf{=M^0\,L^1\,T^{-2}}$

According to the question,

• $\sf{v_i=20\ m\,s^{-1}}$

• $\sf{v_f=50\ m\,s^{-1}}$

• $\sf{t=10\ s}$

Then, acceleration is,

$\sf{\longrightarrow a=\dfrac{v_f-v_i}{t}}$

$\sf{\longrightarrow a=\dfrac{50\ m\,s^{-1}-20\ m\,s^{-1}}{10\ s}}$

$\sf{\longrightarrow a=\dfrac{(50-20)\ m\,s^{-1}}{10\ s}}$

$\sf{\longrightarrow a=\dfrac{30\ m\,s^{-1}}{10\ s}}$

$\sf{\longrightarrow\underline{\underline{a=3\ m\,s^{-2}}}}$

This is the acceleration of the object.

Answer 2

Answer:

a =3 m s-²

Explanation:

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