Question

8. The velocity of flow of an ideal liquid in a horizontal pipe is 8.0 ms Determine the 'velocity-head'
of the liquid. (g = 10 m/s)
Ans. 3.2 m.​

Answer 1

Answer:

Explanation:

Please mark me brainliest

It's my dream to become a brainliest

Answer 2

Answer:

The velocity head is 3.2 m.

Explanation:

Here we have been given to find the velocity head of the given horizontal pipe where the velocity of flow is 8m/s

We know that the formula for velocity head is as below:

Velocity head = $\frac{u^{2} }{2g}$

where u is the velocity of the pipe and g is the acceleration generated due to gravity.

Here know that g = 10$ms^{-2}$ and u = 8 m/s

Putting these values we calculate the velocity head as follows;

∴ Velocity head = $\frac{8^{2} }{2(10)}$

⇒ Velocity head = $\frac{64}{20}$

⇒ Velocity head = $\frac{32}{10}$

⇒ Velocity head = 3.2 m

Therefore the velocity head is 3.2 m