Question

8. There are two candidates, A and B from a constituency
in an election. The total number of voters in the
constituency is 82,000 and 80% of the total votes
were polled. If 56% of the polled votes were cast in
favour of A, how many votes were polled in favour
of B?​

Answer 1

80% of 82,000 votes =

$\frac{80}{100} \times 82000$

$= 65600$

Thus, 65,000 votes have been cast.

Out of these, 56% votes were pooled in favour of B.

Hence, 44% votes were polled in favour of A. (100% - 56%)

$= \frac{44}{100} \times 65000$

$= 28600$

Finally, 28,600 votes were polled in favour of B.

Answer 2

Answer:

28600

Step-by-step explanation:

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